Question

How would you do this?

Answer 1

Look for perfect squares. Split them up first. Multiply answer with any values already outside radical.

\[2\sqrt{20xy^2}\]

Answer 2

break it down into its constituent parts .... the primes then gather up all the elements that are in pairs.

Answer 3

\[2\sqrt{20xy^2}\]
\[2\sqrt{2.2.5~xyy}\]
\[2\sqrt{2.2}\sqrt{5~x}\sqrt{yy}\]
\[2.2.y\sqrt{5~x}\]

Answer 4

Okay thanks :) I got it right but I did it differently...how did you get 2.2.5?

Answer 5

20 = 4.5 = 2.2.5

Answer 6

broke it into its prime factors is all

Answer 7

Okay now I see what you did...thanks :)

Answer 8

spose we had a perfect square that we just didnt know what a perfect square .... the prime factors would then be useful to pair up is all

Answer 9

perhaps we tried:

10.2 no perfects there

5.2.2 now we have a pair :) but yeah, your way was fine

Answer 10

Okay :)