Mathematics
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OpenStudy (anonymous):
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OpenStudy (evanhelps):
To rationalize a denominator, you want to get rid of the root symbols from the bottom
OpenStudy (evanhelps):
So the denominator here is \[\sqrt{8x}\] and you want to get rid of it's root symbol.
OpenStudy (evanhelps):
So multiply both the top and the bottom by root x. So you get \[\sqrt{5}*\sqrt{8x}\] on the top
OpenStudy (evanhelps):
And on the bottom \[\sqrt{8x}*\sqrt{8x}=8x\]
OpenStudy (evanhelps):
So you are left with \[\sqrt{40x}/8x\]
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OpenStudy (evanhelps):
How would you simplify from there?
OpenStudy (evanhelps):
Hint: simplest radical form for the \[\sqrt{40x}\]
OpenStudy (evanhelps):
No, it's no just 8x without the roots.
OpenStudy (evanhelps):
Now*
OpenStudy (evanhelps):
No, you can break it into it's simplest radical form, which is \[\sqrt{40x}=\sqrt{4}*\sqrt{10x}=2\sqrt{10x}\]
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OpenStudy (evanhelps):
So now you have 2\[2\sqrt{10x}/8x\]
OpenStudy (evanhelps):
So divide both the bottom and top by 2, and what do you get?
OpenStudy (evanhelps):
Yup
OpenStudy (evanhelps):
Well imagine \[\sqrt{25}*\sqrt{25}\]
OpenStudy (evanhelps):
Which is equivalent to 5 * 5
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OpenStudy (evanhelps):
Which equals 25
OpenStudy (evanhelps):
That's how I think about it
OpenStudy (evanhelps):
Welcome :)