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Mathematics 13 Online
OpenStudy (anonymous):

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OpenStudy (evanhelps):

To rationalize a denominator, you want to get rid of the root symbols from the bottom

OpenStudy (evanhelps):

So the denominator here is \[\sqrt{8x}\] and you want to get rid of it's root symbol.

OpenStudy (evanhelps):

So multiply both the top and the bottom by root x. So you get \[\sqrt{5}*\sqrt{8x}\] on the top

OpenStudy (evanhelps):

And on the bottom \[\sqrt{8x}*\sqrt{8x}=8x\]

OpenStudy (evanhelps):

So you are left with \[\sqrt{40x}/8x\]

OpenStudy (evanhelps):

How would you simplify from there?

OpenStudy (evanhelps):

Hint: simplest radical form for the \[\sqrt{40x}\]

OpenStudy (evanhelps):

No, it's no just 8x without the roots.

OpenStudy (evanhelps):

Now*

OpenStudy (evanhelps):

No, you can break it into it's simplest radical form, which is \[\sqrt{40x}=\sqrt{4}*\sqrt{10x}=2\sqrt{10x}\]

OpenStudy (evanhelps):

So now you have 2\[2\sqrt{10x}/8x\]

OpenStudy (evanhelps):

So divide both the bottom and top by 2, and what do you get?

OpenStudy (evanhelps):

Yup

OpenStudy (evanhelps):

Well imagine \[\sqrt{25}*\sqrt{25}\]

OpenStudy (evanhelps):

Which is equivalent to 5 * 5

OpenStudy (evanhelps):

Which equals 25

OpenStudy (evanhelps):

That's how I think about it

OpenStudy (evanhelps):

Welcome :)

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