Is this picture correct ?
|dw:1401782979678:dw|
the line is meant to be y=x
It is ok. The line y=x bisects the first and third quadrant, so it is ok.
y=x passes through 45 degrees
So it is correct
Thank you :) What are the co-ordinates for the point of intersection ? That means where the two lines I have drawn meet isn't it ?
In the graph, I see only one line and the axis x-y. If you mean where the line cut these axes, you'll see that the point is (0,0).
The axis lines do not count as actual lines
Sorry ! I forgot I'm not on my other post ! @No.name would understand that previous question. I meant with the line we drew last night.
Ok.
@No.name Where'd that big post go ? I was reading and it disappeared :(
Is this the question you need to find out ? Ok, the equation of the line last night we drew was y= 4x -9 The equation of the line this time is y=x So we need to solve them simultaneously y-4x= -9 --->1 y-x = 0------>2 We subtract 2 from 1 3x = -9 x= -9/3 x= -3 Substitute the value of x into any of the above eqautions 1 and 2 You would get the value of y After that Write it as (value of x , value of y ) This is the point where the two lines intersect
so they intersect at -4,-9
I am not commenting wether it is correct or not but how did u do that
well subtract 2 from 1. x-x is nothing y-y is nothing that leaves -4 and -9
no it isn't correct i am sorry, -4x is whole quantity u subtract -x from it u get -(-) = + So we get x = -3 It is better you ask your teacher because explaining through OS is difficult if you don't know the basics :-)
okay so can you draw out the working for that for me please ? I cant really talk to a teacher as im in an online university course and seeing a lecturer is nearly impossible. Its a kinda fend for yourself thing.
It cannot be drawn , it is analytical not graphical
so what can be shown for working out ? is it just a knowing thing ?
I just showed the working above ^
y-4x= -9 --->1 y-x = 0------>2 We subtract 2 from 1 3x = -9 x= -9/3 x= -3
yes :-
so x=-3 on its own is correct ?
(-3, value of y ) Find the value of y now y-(-3) = 0 y+3 = 0 y = -3 So they will intersect at (-3, -3) END OF STORY
oh im sorry ..
thank you ..
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