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Mathematics 17 Online
OpenStudy (anonymous):

Idk how to do this... fan and metal + testimonial... thx :D

OpenStudy (anonymous):

Do what exactly?

OpenStudy (anonymous):

sorry... was posting from phone... hard to figure out the site on a phone... but...

OpenStudy (anonymous):

Sorry.. on my phone... hard tofigu

OpenStudy (anonymous):

@Clueless_math

OpenStudy (anonymous):

sorry... dog unplugged computer :P

OpenStudy (anonymous):

No problem. Do you want me to talk you through it, or just give you the answer?

OpenStudy (anonymous):

ummm... can you give me the answer and then explain it please? THANK YOU SO MUCH!!!!

OpenStudy (anonymous):

Sure. 26.4N;51.8 degrees First break the two down into their x and y components. Do this with the formula: (r1 cos theta + r2 cos theta, r1 sin theta + r2 sin theta) (14*cos(104)+21*cos(20),14*sin(104)+21*sin(20)) then you will have the (x,y) of the resultant vector. (16.3466,20.7666) to get the magnitude use the formula: sqrt(x^2+y^2) sqrt(16.3466^2+20.7666^2) 26.4N to get the direction use this formula: arctan(y/x) arctan(20.7666/16.3466) 51.22 degrees That is not exactly 51.8 degrees but it is really close, so we can chalk the discrepancy up to rounding differences.

OpenStudy (anonymous):

Thank you very very very much :D

OpenStudy (anonymous):

Do you understand all that?

OpenStudy (anonymous):

yes :) and thank you for the formula for the first step... when i found a place that explained it, it didn't give the formula, it just said break it down into the x and y components. makes so much sense in ur explanation :D

OpenStudy (anonymous):

Happy to be of assistance!

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