medal && fan ! a food company makes regular and tall soup cans. The area of the base of both cans is 5 cm^2. The volume of the regular can is 40cm^3 The tall can is 2 cm taller. What is the volume of the tall soup can?
@Jennjuniper
1st, whats the equation for a cylinder?
\[\pi r ^{2} h\] or (Base area)(height)
so. try plugging in the variables you already have.
@_DimondLife_
sorry im working on a test right now and its time give me a couple of mins please,
no problem.
yesterday i got a little busy im so sorry , do you have time to help me now ?
yeah. sure.
okay so what do i do now ?
\[\pi r ^{2} h\] take this equation and plug in the variables you already know.
so its 5 times 10 ?
plug in the variables to the equation so i can see first.
i meant to put 40 not 10 sorry
the \[\pi r ^{2}\] is the area of the base btw.
5
because the base area of both cans is 5cm^2
okay. so the equation is\[40=5h\] right?
yes , and then i do what ?
what do you think? remember, we're trying to isolate the variable here.
do i multiply 40 by 5 or divide it
whatever the action is between the 5 and the h, you do the opposite.
40 divided by 5 = 8
yes! so what is the height of the regular can?
8 ?
yup!
so. what does it say about the regular can versus the large can?
it says the tall can is 2 cm taller what is the volume of the tall soup can ?
well, you need height to find volume. the height is 10 (you did 8+2=10). so what would your equation be? remember, they both have the same base area
idk ? i dont get this stuff at all
\[Volume=Base Area \times height\] insert your variables! c'mon, you can do it!
10 times 5 ?
yeah. just the other way around is all.
So the answer is 50 ?
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