Write an equation of a line perpendicular to y = 1 over 4x + 4 in slope-intercept form that passes through the point (−2, 6).

y= 1 over 4x − 4

y= 1 over 4x + 6

y= −4x − 2

y= −4x + 1 over 4

Question

Write an equation of a line perpendicular to y = 1 over 4x + 4 in slope-intercept form that passes through the point (−2, 6).

 y= 1 over 4x − 4

 y= 1 over 4x + 6

 y= −4x − 2

 y= −4x + 1 over 4

gabylovesyou · Answer

@Compassionate @jim_thompson5910

dan815 · Answer

y=1/4 x + 4 
is a line with slope 1/4
to be perpendicular you have to take negative reciprocal of the slope so
-4/1 = -4
y=-4x+b, now we need to find the right intercept, so that it goes through the point -2,6

dan815 · Answer

6=-4(-2)+b
b=6-8=-2
so 
y=-4x-2

gabylovesyou · Answer

C... Thanks so much! Your explanation is great!