Question

Solve by completing the square: x^2-8x+2=0

Answer 1

\[x^2-8x=-2\] is a start
then what is half of \(8\) ?

Answer 2

4

Answer 3

@satellite73

Answer 4

ok then we go to
\[(x-4)^2=-2+4^2\]

Answer 5

what is \(-2+4^2\) ?

Answer 6

16.2

Answer 7

oh no

Answer 8

\[-2+4^2=-2+16=14\]

Answer 9

now we are at
\[(x-4)^2=14\] take the square root, don't forget the \(\pm\) and get
\[x-4=\pm\sqrt{14}\] then add \(4\) to both sides and finish with
\[x=4\pm\sqrt{14}\]

Answer 10

ok thanks. Can you help me with few more?
@satellite73

Answer 11

k

Answer 12

Solve by completing the square: x^2 +6x-3=0

Answer 13

same idea as last time
start with
\[x^2+6x=3\] then what is half of \(6\) ?

Answer 14

3

Answer 15

k we go right to
\[(x+3)^2=3+3^2\] now (careful) what is \(3+3^2\) ?

Answer 16

12

Answer 17

got it
so
\[(x+3)^2=12\\
x+3=\pm\sqrt{12}\\
x=-3\pm\sqrt{12}\]

Answer 18

ok thanks. and this one too. 2x^2-5x+6=0

Answer 19

this is not so fun to complete the square with
easier to use the quadratic formula
do you know it?

Answer 20

yes i do

Answer 21

ok then for
\[2x^2-5x+6=0\] use the quadratic formula with
\[a=2,b=-5,c=6\] to get your answer

Answer 22

ok ill finish it. can u help me with few more? I would really appreciate it

Answer 23

@satellite73

Answer 24

k

Answer 25

(5x-1)^2 =24

Answer 26

we are half way home at the start
begin with
\[5x-1=\pm\sqrt{24}\]

Answer 27

then add one
get \[5x=1\pm\sqrt{24}\] and finally divide by \(5\) to get
\[x=\frac{1\pm\sqrt{24}}{5}\]

Answer 28

you can also write this as
\[x=\frac{1\pm2\sqrt6}{5}\] if you like

Answer 29

thanks!!! 3x^2 +2x=-4

Answer 30

start with
\[3x^2+2x+4=0\] and use the quadratic formula with
\[a=3,b=2,c=4\]

Answer 31

and next? plz

Answer 32

@satellite73

Answer 33

you mean how to you use the formula?

Answer 34

solve everything with the answer

Answer 35

\[3x^2+2x+4=0\]
\[x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\] with
\[a=3,b=2,c=4\] you get '
\[x=\frac{-2\pm\sqrt{2^2-4\times 3\times 4}}{2\times 3}\]

Answer 36

since the number inside the radical is negative, there is not real solution for this one

Answer 37

so what will be the anwer

Answer 38

no real solution?

Answer 39

@satellite73