Mathematics
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OpenStudy (anonymous):
Circles M and K are congruent, QR=LN and OP= VW. I need to find x and y
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OpenStudy (anonymous):
OpenStudy (anonymous):
@Tommy389
jimthompson5910 (jim_thompson5910):
Since QR=LN, QR = x+y, and LN = 6, this means
QR=LN
x+y=6
jimthompson5910 (jim_thompson5910):
OP = VW
3x-y = VW ... plug in OP = 3x-y
3x-y = 10 ... plug in VW = 10
OpenStudy (anonymous):
ok :)?
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jimthompson5910 (jim_thompson5910):
We now have this system of equations
x+y = 6
3x-y = 10
OpenStudy (anonymous):
yeah?
jimthompson5910 (jim_thompson5910):
Do you know how to solve that system?
OpenStudy (anonymous):
not really :( thats why I need your help!
jimthompson5910 (jim_thompson5910):
If we add the equations, we get
x+y = 6
3x-y = 10
---------
4x+0y = 16
Notice how x+3x = 4x, y+(-y) = 0y, and 6+10 = 16
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jimthompson5910 (jim_thompson5910):
4x+0y = 16
4x+0 = 16
x = ???
OpenStudy (anonymous):
x=4 :)
jimthompson5910 (jim_thompson5910):
now use that to find y
jimthompson5910 (jim_thompson5910):
pick any equation with x,y in it
say we pick x+y = 6
jimthompson5910 (jim_thompson5910):
plug in x = 4 and solve for y
x+y = 6
4+y = 6
y = ??
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OpenStudy (anonymous):
y=2 :) :)
OpenStudy (anonymous):
THANK YOU SO MUCHHH!! you saved mee!
OpenStudy (anonymous):
would you please help me with a few more :)??
jimthompson5910 (jim_thompson5910):
yep x = 4,y = 2
jimthompson5910 (jim_thompson5910):
I can do one more
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OpenStudy (anonymous):
ok thanks!
OpenStudy (anonymous):
just give me a second to draw the circles
jimthompson5910 (jim_thompson5910):
sure thing
jimthompson5910 (jim_thompson5910):
take your time
OpenStudy (anonymous):
Circles M and K are congruent, QR=LN and OP=VW. I need to find y.
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OpenStudy (anonymous):
OpenStudy (anonymous):
I am stuck on this one :(
jimthompson5910 (jim_thompson5910):
Same idea as before
QR = LN
2x = y+12
------------
OP = VW
3x = 19+y
OpenStudy (anonymous):
ok :)?
jimthompson5910 (jim_thompson5910):
One way to solve is to first isolate y in 2x = y+12 to get
2x = y+12
2x-12 = y
y = 2x - 12
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jimthompson5910 (jim_thompson5910):
Then plug this into 3x = 19+y and solve for x
3x = 19+y
3x = 19+2x - 12
x = ???
OpenStudy (anonymous):
x=7 ?
OpenStudy (anonymous):
so, 3(7)=19+2x-12?
OpenStudy (anonymous):
oh, 3(7)=19+2(7)-12?
jimthompson5910 (jim_thompson5910):
x = 7 is correct
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jimthompson5910 (jim_thompson5910):
now use this to find y
y = 2x - 12
y = 2*7 - 12
y = 14 - 12
y = 2
OpenStudy (anonymous):
THANK YOU SO MUCHH!! ill let you go now, thank you so much, couldnt have done it without youu
jimthompson5910 (jim_thompson5910):
I'm sure you could have. I'm glad to be of help.