Question

Which is an equation of the line containing the points (4, 10) and (6, 11) in standard form?

–x + 2y = 16
2x – y = –2
x + 2y = 24
x – 2y = –16

Answer 1

Well first you have to find your slop with the two points

Answer 2

\(\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
&({\color{red}{ 4}}\quad ,&{\color{blue}{ 10}})\quad &({\color{red}{ 6}}\quad ,&{\color{blue}{ 11}})
\end{array}
\\\quad \\

slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies \cfrac{{\color{blue}{ y_2}}-{\color{blue}{ y_1}}}{{\color{red}{ x_2}}-{\color{red}{ x_1}}}
\\ \quad \\

y-{\color{blue}{ y_1}}={\color{green}{ m}}(x-{\color{red}{ x_1}})\qquad \textit{plug in the values and solve for "y"}\\
\qquad \uparrow\\
\textit{point-slope form}\)

Answer 3

okay so y - 10= m (x-4) ?