how do you convert f(x)=x^2-6x-4 to vertex form? Please help i dont understand
Completing the Square!! f(x) = x^2 - 6x + _____ - 4 - _______ Use the 6 to fill in the blanks.
@tkhunny so you put the 6 in those blanks and thank you
No, completing the square is a little trickier. -6/2 = -3 (-3)^2 = 9 Try a 9.
@tkhunny im sorry i dont get it where is the -6/2 and where do you put the 9 in both blanks
It's Completing the Square. You will need this skill. We are exploiting this property \((a+b)^{2} = a^{2} + 2ab + b^{2}\) In the general case, we have \(a^{2}\;and\;2ab\). We just need to find \(b^{2}\). That is how we used the 6 to find the necessary 9. \(f(x) = x^2 - 6x + 9 - 4 - 9 = (x-3)^{2} - 13\), and we're done.
@tkhunny do you only do like terms
I don't understand the question. If you are combining things, yes, they had better be "like terms". 1) We BUILT the perfect square. That's why we needed the 9. 2) Since we added 9, keeping things the same required us to subtract 9. 3) We went to all that trouble to find the 9, don't just recombine it. Use it for what was intended. The first 3 terms are intended to be that perfect square trinomial.
@tkhunny so what do i do exactly do i solve the first 3
?? It's done. Why are you still doing something? That IS the vertex form. It's a little odd with f(x) in there. For the vertex form, that's usually a 'y'. It might be (y+13) = (x-3)^2
@tkhunny oh ok how about the x cordinate and axis of symmetry of this vertex form?
The vertex is staring at you. That's why it's called the Vertex Form. (3,-13) Done. Axis of symmetry goes through the vertex. x = 3, in this case.
@tkhunny ok so the x cordinate would be 3 the y cordinate would be 13 what would be the vertex
@tkhunny vertex would be 3,-13 i think
y = -13. Don't miss the sign. You can also pull the axis of symmetry out of the original function definition. f(x)=x^2-6x-4 x = -(-6)/(2*1) = 6/2 = 3
The parentheses are not optional. (3,-13) Let the notation help you.
@tkhunny ok thanks can you please help me with one more thing
No focus or directrix? So sad!
@tkhunny what
Just other parts of a parabola. It isn't all requested all the time. It will be, some day.
@tkhunny ok thank you for your help
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