Geometry, NEED HELP! WILL GIVE MEDAL!
okay so this one is in steps. first we should get the information we already know. length BD is the same length as the diameter which is 18. AD is the same as the radius which is half of the diameter which equals 9. so there is two of the three sides. to find the angle of DBA use the o/h function which is sine.
For some reason I don't think I learned what the o/h function is. That' or I just can't remember.
o/h=9/18=.5 do inverse sine .5 or archsine .5
thats fine your o/h is sine
Ok. so the sine is .5 What do I use the archsine for?
archsine you use to get the angle in degrees.
Oh! Woah. That' would've been helpful to know. So the archsine is .5?
no archsine OF .5 will get you your answer in degrees if you do this on a calculator it should look something like archsin(.5)= and then that number is your degrees
and yes it's helpful :)
did you get it?
pi/6
no it's the degree of <B or DBA
but pi/6 is equal to 30 degrees
But I already know that Angle B is 30 degrees because the triangle is a right triangle and therefore follows the 30-60-90 triangle thing
well in that case you should now a. and b.
know*
Yes, I guess I should've been more specific. I need help with C, D, and E
haha okay that's fine I can still help. I can show you and very easy way to get length AB
ok
If I find AB then I can do question D on my own. Then I'll just need help with E
however your not suppose to know this until calculus so...shhh haha rename length AD to A rename length AB to B and rename length BD to C to find B use this formula b/sin b=c/sin c this is easy because it's a right triangle. sin of c or sin of 90 =1 sin of b is sin of 60=0.866 now it will look like b/.866=18/1 simplify b/.866=18 multiple both sides by .866 b= 18 x .866 b=15.588
so... the length of AB is 15.5?
that is correct
are you ready for the last one?
The length of the arc?
Also for D then. The relationship is about...
1.7 * length-arc AD = length-arc AB
@Master_General_B_C
sorry I grab something to eat
That's ok.
okay so which do you need help with?
So for D the relationship is about 1.7 * length-arc AD = length-arc AB?
yes it should be
Ok. Now for E
okay
now do you have an arch formula?
No. I would probably have to look in my textbook
hmm...I have one, but it's a calculus one and it might confuse you.
They always say you need the central angle measure but we don't have a central angle.
we can get one :)
make a straight line from E to C and F to C
this will be an equilateral triangle. because they all are the radius length (9)
That would make it about a 45 degree angle right? but how do we know the exact measurement?
the formula is (60/360) x 2pi r and it would be 60 because 60 x 3 = 180
this will give you an answer of 9.42
so. The length of the arc is 9.42? Then what's the measure?
So can you tell me more specifically why it's 60?
60 would be the answer
How is 60 the answer? and what is the 9.42 for then?
sorry I went too far that formula is to find the length you were only looking for the degree. so that formula is nothing to you...yet
so the length is 9.42
yes but you are looking for the degree which is 60
So how does the degree become 60 from 9.42?
forget about the 9.42 that is the length I went too far. go back to when we made the lines from E and F to C. the angle of ECF will be the same angle of the arch of EF
Yes.
so do you get it now?
Not really. How do I know that the angle of ECF is 60 degrees?
okay. if you take a point from the side of a circle to the center that would be the radius. we know the radius is 9 so EC, EF, and FC are all 9. do you get that?
Ok.
so how does that relate to the 60 degrees of the arc?
Sorry, i'm probably making this really hard for you.
because the angles will all be the same. <C, <E, and <F will all be the same angle in degrees (60) the arc length IN DEGREES will be the same as the angle that faces it, in this case <C
oh. ok got it. thanks
you are welcome.
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