Factor completely: 2x^2 + 14x + 12

A.

(x + 1)(x + 6)

B.

2(x + 2)(x + 3)

C.

2(x + 1)(x + 6)

D.

2(x + 2)(x + 6)

Question

Factor completely: 2x^2 + 14x + 12
  
 
 

 
 

  

  A. 
 
(x + 1)(x + 6)
   
   

 
 

  

  B. 
 
2(x + 2)(x + 3)
   
   

 
 

  

  C. 
 
2(x + 1)(x + 6)
   
   

 
 

  

  D. 
 
2(x + 2)(x + 6)

anonymous · Answer

@TechnoSoul

imstuck · Answer

Start this by factoring out the 2.  It will make the coefficient in front of the x^2 term be 1 instead of 2.$$2(x ^{2}+7x+6)$$Now factor what's inside the parenthesis.  That comes to
2(x + 6)(x + 1).  If you were to FOIL that back out and then redistribute the 2, you would be back at your original polynomial.