Question

Could someone help me with this geometry of quadrilaterals problem?

Answer 1

in rectangle opposite sides will be equals so equate ad = bc and ab = cd

Answer 2

I still don't know how to solve it though.

Answer 3

i tried solving it multiple ways.

Answer 4

see ad = bc that will give us equation
x = 2y + 2 -----(1)
and ab = cd will lead to another equation right?
2x = 3y + 5 ------(2)
see we got two equations and we have two unknown variables ( x and y ) solving them
multiplying eq(1) with 2 we get
2x = 4y + 4 ----(3)
- 2x = 3y + 5 -----(2) subtracting it from (3)
----------------------------
0 = y - 1
so we got y -1 = 0 => y = 1
now substitute the y value in any of eq(1) or (2) to get x value and thats it!

Answer 5

had to type a lot :P :D

Answer 6

Oh wow, well thank you, I'm still unsure of how you did it though.

Answer 7

remember the minimum number of equations must always be equal to the number of unknowns
here we had two unknowns x and y so we had to have two equations involving them
and we used rectangle properties to have that eqautions
and we solved it in traditional way @veeveeniko

Answer 8

Oh okay, that makes sense. Thank you so much for helping me, sorry you had to go out of your way to explaining everything with so much detail. I was able to understand it and solve the equation.

Answer 9

no problem :) :P, i liked it :)