Question

a number between 49 and 95 that is a multiple of 3 , 5 , and 9

Answer 1

Hi maggz!
\(\Large\bf \color{#CC0033}{\text{Welcome to OpenStudy! :)}}\)

Answer 2

So for it to be divisible by 5, it must end in 0 or 5.\[\Huge\rm \text{_}0,\qquad\qquad \text{_}5\]For divisible by 3 the `sum` of the digits must be divisible by 3.
And similarly for 9, the sum of the digits must be divisible by 9.

Answer 3

So here is an example:\[\Huge\rm 45\]4+5 = 9
The sum of the digits is 9, which is divisible by 3 and 9.
And it ends in a 5.

So do you think you can come up with a number like this, but in the correct range that they gave? :)