Question

http://papers.xtremepapers.com/CIE/Cambridge%20International%20A%20and%20AS%20Level/Chemistry%20(9701)/9701_w08_qp_1.pdf
Q39

Answer 1

I would say #2 is correct because it results from the most stable radicals generated according to Markovnikov's Rule.

Answer 2

its a multiple choice where the answer is either 1 or 2,3 or 1,2,3 or 1,2

Answer 3

Ah in that case 1 and 2. For #3, you can't generate that particular molecule if you start with two 3-carbon radicals because it would involve breaking a C-C bond, which is not the case for either of the first two molecules.

Answer 4

free radical CH3CH•CH3 will react with CH3CH2CH2•

Answer 5

can you explain once more why molecule 3 is not suitable

Answer 6

In this case you really only have 2 possible radicals for propane, which are the two you wrote above. You can combine two CH3CH•CH3 to produce compound #2, or one of each to produce compound #1. If you take two CH3CH2CH2•, you end up with hexane (not an option here). There is no way to produce compound #3 with these radicals as to do so you would need to either break a C-C bond or use different radicals to begin with (e.g. an ethane radical and a butane radical). Hope that helps!

Answer 7

thank you for your help :D