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Mathematics 21 Online
OpenStudy (anonymous):

Please Confirm my answer! I don't know if this is the correct choice: Which choice is equivalent to the fraction below? (Hint: Rationalize the denominator and simplify.)

OpenStudy (anonymous):

OpenStudy (anonymous):

first of all, your choice is wrong

OpenStudy (anonymous):

That's what I wanted to know, please help me! D:

OpenStudy (anonymous):

how did you get that answer? can you explain?

OpenStudy (anonymous):

Not really:/

OpenStudy (anonymous):

you know how to rationalize right?

OpenStudy (anonymous):

aim of rationalization is to get rid of that square root sign in the denominator

OpenStudy (anonymous):

so, first thing you will observe that you can cancel out 2 as common factor in numerator and denominator

OpenStudy (anonymous):

Well okay...

OpenStudy (anonymous):

\[(2-2\sqrt{2})/(2+2\sqrt{2})=(1-\sqrt{2})/(1+\sqrt{2})\]

OpenStudy (anonymous):

now, our aim is to get rid of that square root sign in the denominator, so you multiply both numerator and denominator by \[\sqrt{2}-1\]

OpenStudy (anonymous):

so, the equivalent fraction will be:\[(1-\sqrt{2})(\sqrt{2}-1)/(\sqrt{2}+1)(\sqrt{2}-1)\]

OpenStudy (anonymous):

as (a+b)(a-b)=a^2-b^2, you will notice that the denominator value becomes 2-1=1 calculate the numerator and let me know what you get

OpenStudy (anonymous):

-2(1-2√x)

OpenStudy (anonymous):

I think I got it.

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