Question

Someone please help me , advanced exam tommorow
JEE QUESTION

Answer 1

\[\huge 3^{x} = 4^{x-1}\]
Find x

Answer 2

Should we take log on both sides

Answer 3

take logarithm in both sides

Answer 4

x log 3 = (x-1) log 4
solve for x

Answer 5

Wait there are options

Answer 6

answer is log4/(log4/3), do the necessary calculations, i have given you the hint how to solve that

Answer 7

(A)\[\frac{ 2\log_3 2}{ 2\log_3 2 -1 }\]
(B)\[\frac{ 2 }{ 2 - \log_2 3}\]
(C)\[\frac{ 1 }{ 1 - \log_4 3}\]
(D)\[\frac{ 2\log_2 3 }{ 2\log_2 3 -1}\]

{It came in Jee(advanced) 2013, Paper2 , (3,-1)/60}---> In case if anyone has any website for sollutions

Answer 8

option B

Answer 9

\[x = - \frac{ \log(4) }{ \log(3) -\log(4) }\]

Answer 10

no negative sign

Answer 11

There would be I am sure , would you please re-confirm if you don't mind :)
Is my answer correct @ganeshie8

Answer 12

Are you here @Arnab09

Answer 13

check again, there will be no negative sign

Answer 14

Hey i think i got it

Answer 15

\[\huge \log_23^{x}= \log_24^{x-1}\]

The R.H.S would become
\[\huge 2(x-1)\]

The L.H.S would become
\[\huge xlog_23\]
\[x= \frac{ 2 }{ 2-\log_2^{3} }\]

Answer 16

that is correct^^ :)

Answer 17

There are multiple options correct

Answer 18

Is anyone really here

Answer 19

A,B,C all are correct

Answer 20

If we try to rearrange we geet A , uhhhhh yes sgot C
Thanks everone

Answer 21

U might want to have a look at this
@mathslover