Question

I will fan and medal anybody who helps me even a little bit right now, this is urgent.

P(n)=-250n^2+2,500n-5,250

Part A: What are the zeroes of the above function and what do they represent? (Please show steps)

Part B: Find the Maximum profit by completing the square of the function P(n). (Please show steps)

Part C: What is the axis symmetry of the function P(n)


Sorry if it's confusing but that's why I need help, Thank you in advance if you help! :)

Answer 1

Please I really need help on this guys

Answer 2

I'll Help!

Answer 3

Thank you so much please do help, Im seriously so stuck on this I will medal you like a thousand times

Answer 4

"A) P(n) means the profit of selling tickets at n price. So, say P(12) = 10,000. This means the profit is $10,000 if the they decide to sell the concert tickets at $12 each.

find zeros means find what value of n gives P(n) = 0. suppose n is, like P(500) = 0, this means there would be no profit if each ticket cost like $500 each. Of course you to find the actual value of n that makes the equations equal 0."

Answer 5

THAT should help you with the first one

Answer 6

so the first section is equal to zero..?

Answer 7

Oh wait okay I get it sort of

Answer 8

Ok, for the second one, you just have to factor out the answer to that equation

Answer 9

P(n) = -250n2 + 2,500n - 5,250 "zeros" would mean

-250n^2 + 2500n - 5250 = 0 you can factor out a -250

-250 (n^2 - 10n + 21) = 0

Now factor this: n^2-10n+21, Do you know how? If not i'll help.

Answer 10

Yes it would be (n-3)(n-7) right..?

Answer 11

Yes

Answer 12

Now you have (n) = 3 or 7 the profitof this answer would equal to zero. This was still kinda the answer for Part A. No worries though, Part b is next :)

Answer 13

And part b is much more easier :)

Answer 14

Okay no problem :)

Answer 15

Part B. To complete the square is use n^2 - 10n + 25 = (n-5)^2
then factor and you get n^2 - 10 + 21. so -250(n^2-10n+21+4-4)
-250( (n-5)^2 - 4)
-250 (n-5)^2 + 1000. so n-5=0 and solving for n you get n=5

Answer 16

That's pretty much the answer for part b, and for part C, youll get your answer based on the graph to this equation and the graph looks like this...

Answer 17

:)

Answer 18

Thank you so so much ..could you help me with ONE more with 2 parts to it? If not I will still give you a medal, you have helped me a lot :)

Answer 19

Sure

Answer 20

Okay I will put it in a new question and tag you so you can get another medal :)

Answer 21

ok :)