Question

Need help with some math questions?

Answer 1

1. Multiply. x^2 + 8x + 15/x - 4 * x^2 - 16/2x + 6

A. x^4 + 8x - 1/3x + 2
B. (x + 5)(x + 4)/2
C. (x - 5)(x + 4)/2
D. x^4 + 8x^3 - x/2x^3 - 24

Answer 2

Does the problem look like \[\frac{x^2 + 8x + 15}{x - 4}\frac{ x^2 - 16}{2x + 6 }\]

Answer 3

Yeah @AnimalAin .-. i think the answer may be B but im not sure

Answer 4

If it does\[\frac{x^2 + 8x + 15}{x - 4 }\frac{ x^2 - 16}{2x + 6 }=\frac{(x+3)(x+5)}{x-4}\frac{(x+4)(x-4)}{2(x+3)}\]\[=\frac{(x+5)(x+4)}{2}\]I would say your estimate is correct.

Answer 5

Key steps for this kind of problem:

1. Factor.
2. Cancel.
3. Simplify.

Answer 6

Thanks :D

Answer 7

Can you help with one more? :o

Answer 8

No sweat. Do math every day.

Answer 9

Sure. What's the question?

Answer 10

Solve x+12/x+4=x/x+8

Answer 11

x= -4
x= 8
x= 6
x= -6

Answer 12

Is this the problem?\[\frac{x+12}{x+4}=\frac{x}{x+8}\]

Answer 13

Yup!

Answer 14

This equation is a proportion, a statement two ratios are equal. We solve them in grade school by cross multiplication. Here, we do effectively the same thing by multiplying both sides by the common denominator.

Answer 15

\[\frac{x+12}{x+4}=\frac{x}{x+8} \implies (x+12)(x+8)=x(x+4)\]

Answer 16

From there, multiply both sides, combine the like terms, and solve the problem.

Answer 17

You might get something that looks similar to\[x^2 +20x+96=x^2+4x \implies 16x=-96 \implies x=-6\]

Answer 18

Does that seem doable?

Answer 19

It does. Where exactly did the 96 come from though.

Answer 20

Isn't that eight times twelve on the FOIL of the two factors?

Answer 21

OH right! I think it's pretty easy to forget important steps in math. and would explain why my answer was -4. But thanks :D Really appreciated the help :)

Answer 22

No sweat. Do math every day.