A particle moves with constant speed 'v' along a regular hexagon ABCDEF in the same order. Then the magnitude of the average velocity for its motion from A to F is ? , A to D is ? , A to C is ? , A to B is ?

Question

A particle moves with constant speed 'v' along a regular hexagon ABCDEF in the same order. Then the  magnitude of the average velocity for its motion from A to F is ? , A to D is ? , A to C is ? , A to B is ?

theeric · Answer

|dw:1402112336842:dw|

theeric · Answer

|dw:1402112417737:dw|

theeric · Answer

Since it's a REGULAR polygon, it's symmetrical. So opposite sides are parallel. And I drew the arrows in to indicate direction.

Drawing pictures is usually a good way to start! It helps you see the problem and tests if you really understand it.

You need to find the average velocity. That is the average change in displacement over time. The time for each side will be the same because it is the same speed and distance.

theeric · Answer

What will really help is the the average velocity is the total change in displacement divided by the total change in time. Time can be measured in segments, and displacement can be found geometrically.

As an example, from A to E is|dw:1402113903004:dw|this displacement, divided by four segments of time.