Question

Can someone please help me with this question? I'm not sure how to do it.

Answer 1

ok first do you know what the quadratic formula is

Answer 2

Yeah

Answer 3

what is it?

Answer 4

x=b+squareroot b^2-4ac / 2a

Answer 5

yes ok

Answer 6

so you have to identify a,b,and c

Answer 7

Okay, so A=2, B=4, and C = 7?

Answer 8

A=-2,B=-4,and C=-7 because you have to move the 4x to the other side

Answer 9

Oh okay, so then do i just plug a, b, & c into the formula?

Answer 10

yes

Answer 11

I got 56?

Answer 12

x=56?

Answer 13

None. a = -2, b - 4, c = -7.

plug these values in formula \(\Large \dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\)

Answer 14

do you still need help

Answer 15

\(\bf -2x^2-7=4x\implies -2x^2-4x-7=0
\\ \quad \\

\textit{quadratic formula}\\
y={\color{blue}{ -2}}x^2{\color{red}{ -4}}x+{\color{green}{ -7}}
\qquad \qquad
x= \cfrac{ - {\color{red}{ b}} \pm \sqrt { {\color{red}{ b}}^2 -4{\color{blue}{ a}}{\color{green}{ c}}}}{2{\color{blue}{ a}}}\)

is not 56 btw

Answer 16

nice visualization

Answer 17

Thanks everyone!