PLEASEEEE HELPPPPP MEEEEEEE. I think it is 43 48. In the circle, mBC = 86°. The diagram is not drawn to scale. What is m∡BCP? (1 point) 43° 86° 90° 172°
Can you help?
Yes, you are correct
OMG THANKS. I have another.
53. What is the equation of the circle with center (–4, –3) that passes through the point (6, 2)? (1 point) (x – 4)2 + (y – 3)2 = 25 (x – 4)2 + (y – 3)2 = 125 (x – (–4))2 + (y – (–3))2 = 25 (x – (–4))2 + (y – (–3))2 = 125
what is your choice?
Im between b and d
go ahead, so far so good. Now, make decision
Okay. b?
hahahaa.... Are you sure?
no, thats why im asking for help
don't forget center is (-4,-3)
not (4,3)
ohh okay so d
Again, sure??
trust yourself
uhm no. I was thinking b or d because of the 125 at the end. Im really bad at this. Can you help me?
(x-h) ^2 + (y-k)^2 = r^2 h = (-4) ; k = (-3) so \(\Large (x- (-4)^2 ...\) is the correct one. So??
andd im confused. would it be a then?
d is correct one a has the left hand side is ok, but the right hand side =25 makes it wrong
oh. I guess i shouldnt second guess myself. Can you help me with another?
just post, If I can, I will.
52. What is the standard equation of the circle in the graph? (x + 3)2 + (y – 2)2 = 9 (x – 3)2 + (y + 2)2 = 9 (x – 3)2 + (y + 2)2 = 3 (x + 3)2 + (y – 2)2 = 3
don't you know how to do or you just get stuck at some where? Tell me what do you have so far
I dont know this one at all. I failed the circle part of all my test this semester
Hint: find the coordinate of center . I mean (h,k)
-2,2?
(-3,2) check whether I am right or not
Oh yes yourr right. I didnt realize it was by 2s
confirm (h, k) =(-3,2); separate them , we have h =-3, k =2 right? I cheat a little bit on the radius. hihihi from the center, you count the horizontal direction, what is the radius? |dw:1402090495227:dw|
is the radius 2?
it is 3 units , right? so r =3 now you have (h,k) you have radius =3 just plug all into the formula |dw:1402090670566:dw|
ah 3?
so?? the answer is??? Work on it?? don't wait for me. I won't do your homework.
is it c?
hey, you guess??? NO!! you have radius =3 , if it is c, how r^2 =3 still?
I really dont understand this. Can you show me how to do it for next time? Im not asking you do give me the answer right off. Explain
next time? not now?
After looking at it i think its d? Can you review that and check it?
ok, I explain it now, h = -3 , k =2 radius r =3 . The equation of the circle is \[(x-\color{red}{h})^2 + (y-\color{blue}{k})^2=r^2\\(x-\color{red}{(-3)})^2 + (y-\color{blue}{2})^2=3^2\\(x\color{red}{+3})^2 + (y-\color{blue}{2})^2=9\]
Oh so its a
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