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Mathematics 12 Online
OpenStudy (anonymous):

PLEASEEEE HELPPPPP MEEEEEEE. I think it is 43 48. In the circle, mBC = 86°. The diagram is not drawn to scale. What is m∡BCP? (1 point) 43° 86° 90° 172°

OpenStudy (anonymous):

OpenStudy (anonymous):

Can you help?

OpenStudy (loser66):

Yes, you are correct

OpenStudy (anonymous):

OMG THANKS. I have another.

OpenStudy (anonymous):

53. What is the equation of the circle with center (–4, –3) that passes through the point (6, 2)? (1 point) (x – 4)2 + (y – 3)2 = 25 (x – 4)2 + (y – 3)2 = 125 (x – (–4))2 + (y – (–3))2 = 25 (x – (–4))2 + (y – (–3))2 = 125

OpenStudy (loser66):

what is your choice?

OpenStudy (anonymous):

Im between b and d

OpenStudy (loser66):

go ahead, so far so good. Now, make decision

OpenStudy (anonymous):

Okay. b?

OpenStudy (loser66):

hahahaa.... Are you sure?

OpenStudy (anonymous):

no, thats why im asking for help

OpenStudy (loser66):

don't forget center is (-4,-3)

OpenStudy (loser66):

not (4,3)

OpenStudy (anonymous):

ohh okay so d

OpenStudy (loser66):

Again, sure??

OpenStudy (loser66):

trust yourself

OpenStudy (anonymous):

uhm no. I was thinking b or d because of the 125 at the end. Im really bad at this. Can you help me?

OpenStudy (loser66):

(x-h) ^2 + (y-k)^2 = r^2 h = (-4) ; k = (-3) so \(\Large (x- (-4)^2 ...\) is the correct one. So??

OpenStudy (anonymous):

andd im confused. would it be a then?

OpenStudy (loser66):

d is correct one a has the left hand side is ok, but the right hand side =25 makes it wrong

OpenStudy (anonymous):

oh. I guess i shouldnt second guess myself. Can you help me with another?

OpenStudy (loser66):

just post, If I can, I will.

OpenStudy (anonymous):

52. What is the standard equation of the circle in the graph? (x + 3)2 + (y – 2)2 = 9 (x – 3)2 + (y + 2)2 = 9 (x – 3)2 + (y + 2)2 = 3 (x + 3)2 + (y – 2)2 = 3

OpenStudy (loser66):

don't you know how to do or you just get stuck at some where? Tell me what do you have so far

OpenStudy (anonymous):

I dont know this one at all. I failed the circle part of all my test this semester

OpenStudy (loser66):

Hint: find the coordinate of center . I mean (h,k)

OpenStudy (anonymous):

-2,2?

OpenStudy (loser66):

(-3,2) check whether I am right or not

OpenStudy (anonymous):

Oh yes yourr right. I didnt realize it was by 2s

OpenStudy (loser66):

confirm (h, k) =(-3,2); separate them , we have h =-3, k =2 right? I cheat a little bit on the radius. hihihi from the center, you count the horizontal direction, what is the radius? |dw:1402090495227:dw|

OpenStudy (anonymous):

is the radius 2?

OpenStudy (loser66):

it is 3 units , right? so r =3 now you have (h,k) you have radius =3 just plug all into the formula |dw:1402090670566:dw|

OpenStudy (anonymous):

ah 3?

OpenStudy (loser66):

so?? the answer is??? Work on it?? don't wait for me. I won't do your homework.

OpenStudy (anonymous):

is it c?

OpenStudy (loser66):

hey, you guess??? NO!! you have radius =3 , if it is c, how r^2 =3 still?

OpenStudy (anonymous):

I really dont understand this. Can you show me how to do it for next time? Im not asking you do give me the answer right off. Explain

OpenStudy (loser66):

next time? not now?

OpenStudy (anonymous):

After looking at it i think its d? Can you review that and check it?

OpenStudy (loser66):

ok, I explain it now, h = -3 , k =2 radius r =3 . The equation of the circle is \[(x-\color{red}{h})^2 + (y-\color{blue}{k})^2=r^2\\(x-\color{red}{(-3)})^2 + (y-\color{blue}{2})^2=3^2\\(x\color{red}{+3})^2 + (y-\color{blue}{2})^2=9\]

OpenStudy (anonymous):

Oh so its a

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