Question

Find the cosine of both angle A and angle B

Answer 1

ok what you do is open A

Answer 2

where is goes to mark 0 and under it is A

Answer 3

@zzr0ck3r can you help on this

Answer 4

\(sin\ \theta =\frac{opposite}{hypotenuse},cos\ \theta =\frac{adjacent}{hypotenuse}, tan\ \theta =\frac{opposite}{adjacent} \)

Answer 5

yea thats it

Answer 6

SOH CAH TOA ^^^^^^

Answer 7

remember it, it saves lives:)

Answer 8

cos-=10/24

Answer 9

i think its that

Answer 10

plug into calc

Answer 11

I'm dyslexic so its very hard for me to remember that....

Answer 12

thank you! I have no clue on how to do this :(

Answer 13

i know how to do it but i dont have an calc with me atm

Answer 14

yea

Answer 15

use calc and put

Answer 16

2nd cos(10/24

Answer 17

so we are dealing with cosin

so CAH

cos(x) = adjacent/hypotenuse = 24/26

Answer 18

dont use calculator, this cant be any easier

look at the picture and what is the adjacent side to A? its 24
what is the hypotonuse of the triangle 26

SOH CAH TOA

cos(x) = 24/26

Answer 19

yea what he said

Answer 20

so you don't actually have to solve anything? Its about identifing the angles?

Answer 21

"Find the cosine of both angle A:" Looking at the diagram, what is the length of the side adjacent to Angle A? What is the length of the hypotenuse? We need this info because, as @Chibi_Robo3 has typed out for our reference, \[\cos\ \theta =\frac{adjacent}{hypotenuse}\]

Answer 22

adj side length = ??
hypotenuse = ??

Answer 23

adj would be 24 right?

Answer 24

Yes. Great.

Answer 25

hypotenuse is the longest side so 26?

Answer 26

Just a reminder: the hypotenuse is the longest side of a right triangle.

Answer 27

the cos would be 24/26?

Answer 28

Again, you're right. Therefore, \[\cos ~A=\frac{ adj }{ hyp }=\frac{ ?? }{ ?? }\]

Answer 29

Third time in a row: You're right. Happy for you. Bet you can now find cos B, sin B and sin A (if you want the add'l practice).

Answer 30

Basically you must know the definitions of the six trig functions.

Answer 31

thank you all so much! I will be looking up the definitions

Answer 32

Again, they are well worth understanding, remembering and practicing. Good luck!!