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Mathematics 22 Online
OpenStudy (anonymous):

Fan and Medal Divide. Show all work. Make sure to simplify. Assume no denominator equals zero.

OpenStudy (anonymous):

OpenStudy (anonymous):

@aajugdar

OpenStudy (epoweritheta):

factorize and show me ur work

OpenStudy (anonymous):

I don't know how to factorize the numerator on the first one

OpenStudy (anonymous):

You mean \[x ^{2}-144\]

OpenStudy (anonymous):

Yass

OpenStudy (anonymous):

Factoring a perfect square...144 is a perfect square. What is the square root of 144?

OpenStudy (anonymous):

12

OpenStudy (anonymous):

Factoring a perfect square...\[x ^{2}-C = (x+\sqrt{c}) \times (x-\sqrt{c})\]

OpenStudy (anonymous):

So \[x^{2}- 144 =?\]

OpenStudy (anonymous):

(x+12)(x-12), I think

OpenStudy (anonymous):

Now factor the denominator

OpenStudy (anonymous):

I don't think there's two numbers when multiplied give you 7, and when multiplied give you -60.

OpenStudy (anonymous):

when added. sorry

OpenStudy (anonymous):

Two numbers that are multiplied together to give you -60 and when ADDED to gether give you 7. So what two number do that?

OpenStudy (anonymous):

12 and -5

OpenStudy (anonymous):

(x-12)(x-5)

OpenStudy (anonymous):

I mean (x+12)(x-5)

OpenStudy (anonymous):

Ok now factor the other side of the equation and show me what we have.

OpenStudy (anonymous):

Im not sure because 45 doesn't have a perfect square

OpenStudy (anonymous):

It does not factor as a perfect square because x is not squared. What goes into both 9x and 45?

OpenStudy (anonymous):

9

OpenStudy (anonymous):

So the factor would be 9(x-5). And the factor for 3x-36 would be?

OpenStudy (anonymous):

(x-6)(x+6)

OpenStudy (anonymous):

There is no\[x ^{2}\]

OpenStudy (anonymous):

6(x-6)

OpenStudy (anonymous):

No try again.

OpenStudy (anonymous):

What number goes into 3 and 36?

OpenStudy (anonymous):

3(x-12)

OpenStudy (anonymous):

Yes..So can you show me the factored equation now.

OpenStudy (anonymous):

(x+12)(x-12) / (x+12)(x-5) divided by 3(x-12) / 9(x-5) does it have to be simplified, or is already?

OpenStudy (anonymous):

We have more to do..on the right side \[(x+12)(x+12) / (x+12)(x-5)\] How can you simplify this more?

OpenStudy (anonymous):

wait isn't it (x+12)(x-12)

OpenStudy (anonymous):

On both sides there is (x+12) do they cancel out?

OpenStudy (anonymous):

Right. so now we have \[\frac{ (x-12) }{ (x-5) }\div \frac{ 3(x-12) }{ 9(x-5) }\]

OpenStudy (anonymous):

No they do not cancel out.

OpenStudy (anonymous):

That still isn't completely simplified?

OpenStudy (anonymous):

Correct. How would you divide this?

OpenStudy (anonymous):

Multiply?

OpenStudy (anonymous):

the numerator by the denominator of the other side

OpenStudy (anonymous):

You multiply but since we are dividing you have to invert the fraction on the right side then cross multiply. Example below.\[\frac{ 3 }{ 4 }\div \frac{ 2 }{ 3 } = \frac{ 3 }{ 4 } \times \frac{ 3 }{ 2 }\]

OpenStudy (anonymous):

Then you cross multiply and simplify.

OpenStudy (anonymous):

so basically (x-12)*9(x-5) and (x-5)* 3(x-12)

OpenStudy (anonymous):

Yep..

OpenStudy (anonymous):

What cancels out?

OpenStudy (anonymous):

The only thing common is x

OpenStudy (anonymous):

Are yu sure???\[\frac{ 9(x-12)(x-5) }{ 3(x-12)(x-5) }\]

OpenStudy (anonymous):

And 3

OpenStudy (anonymous):

So you answer is?

OpenStudy (anonymous):

3(x-12)(x-5)

OpenStudy (anonymous):

The (x-12) and (x-5) cancel out correct.|dw:1402163014956:dw|

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