Question

PLEASE HELP

Use the quadratic formula to solve 2y^2 – 10y + 8 = 0.









A.

{–4, –1}








B.

{4, –1}








C.

{–4, 1}








D.



{4, 1}

Answer 1

@GotToLoveJenny

Answer 2

For an expression of the form:
ax² + bx + c = 0,
the quadratic formula is:
x = [ -b ± √(b² - 4ac) ] / 2a

In your case, the variable is y, but it is the same thing.
2y² - 10y + 8 = 0

a = 2
b = -10
c = 8

y = [ -b ± √(b² - 4ac) ] / 2a
y = [ -(-10) ± √((-10)² - 4(2)(8)) ] / 2(2)
y = [ 10 ± √(100 - 64) ] / 4
y = [ 10 ± √36 ] / 4
y = [ 10 ± 6 ] /4

Therefore, two cases:
y = (10 - 6) / 4 = 4/4 = 1
or
y = (10 + 6) / 4 = 16/4 = 4

Double-check:
If you factor that, you get:
2(y - 1)(y - 4) = 0
and the same answers for y = 1 or y = 4

Also, if you plug in the values, you should get a true statement:
y = 1:
2(1)² - 10(1) + 8 =? 0
2 - 10 + 8 = 0 (correct)

y = 4:
2(4)² - 10(4) + 8 =? 0
32 - 40 + 8 = 0 (correct)
Answer:
y = 1 or y = 4

Answer 3

Use the quadratic formula to solve 2y2 – 3y = 2.









A.

{–½, –2}








B.

{–½, 2}








C.

{½, –2}








D.

{½, 2}

Answer 4

do you need help on the first on or second one?

Answer 5

second

Answer 6

kk

Answer 7

y={-1/2, 2} Correct Answer B.