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OpenStudy (anonymous):
If y = u^3 and x=5u^2 .
The value of dy/dx at u = 10 is
OpenStudy (anonymous):
@mathslover
OpenStudy (anonymous):
@iambatman
OpenStudy (vishweshshrimali5):
FInd out
\(\cfrac{dy}{du}\) and \(\cfrac{dx}{du}\)
Divide them, you will get \(\cfrac{dy}{dx}\)/
OpenStudy (anonymous):
i have encountered such problem for the first time
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OpenStudy (anonymous):
dy/dx = 3x^2
OpenStudy (vishweshshrimali5):
Plug in the value of u and you will get your answer.
Actually such type of differentiation is called parametric differentiation.
OpenStudy (vishweshshrimali5):
You must obtain the value of dy/dx in terms of u.
OpenStudy (anonymous):
dx/du = 10u
OpenStudy (anonymous):
3x^2/10u
3x^2/20
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OpenStudy (vishweshshrimali5):
Yeah
OpenStudy (vishweshshrimali5):
Now what is dy/du
OpenStudy (marissalovescats):
I feel like I am now ahead in the Calculus world by learning.
I didn't learn this in AP Calc AB.. But maybe next year in AP Calc BC but now have a clue about so woo head start oh yeah.
OpenStudy (marissalovescats):
Words are missing from my sentence, but you get the idea. No judgement I just woke up.
OpenStudy (anonymous):
Never encountered such problem before , thanks @vishweshshrimali5 and @iambatman
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OpenStudy (anonymous):
answer is 3 actually
OpenStudy (anonymous):
:(
OpenStudy (vishweshshrimali5):
Yeah that's correct.
OpenStudy (anonymous):
how?
OpenStudy (vishweshshrimali5):
@No.name what is the value of dy/du ?
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OpenStudy (anonymous):
3x^2/20
OpenStudy (vishweshshrimali5):
Please tell me the value in terms of u only
OpenStudy (anonymous):
3x^2/10u
OpenStudy (vishweshshrimali5):
See, its nothing different than dy/dx.
Just ignore that you have x. You only have y in terms of u. I am asking you to differentiate y with respect to u.
OpenStudy (vishweshshrimali5):
I am writing the question again for you:
\(\color{blue}{\text{Originally Posted by}}\) @No.name
If y = u^3
The value of dy/du at u = 10 is
\(\color{blue}{\text{End of Quote}}\)
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OpenStudy (vishweshshrimali5):
@No.name can you find out the answer of this question ?
myininaya (myininaya):
\[\frac{dy}{dx}=\frac{dy}{du} \cdot \frac{du}{dx}\]
finding dy/du is pretty straight forward.
you can find du/dx by first finding dx/du.
OpenStudy (vishweshshrimali5):
@No.name , can you find out dy/du or not ?
OpenStudy (anonymous):
3u^2 ?
OpenStudy (vishweshshrimali5):
Yes
Now try finding out dx/du.
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OpenStudy (anonymous):
10u
OpenStudy (vishweshshrimali5):
Great
OpenStudy (anonymous):
Sorry my net is not functioning well , so taking time to reply