Question

Will medal! Algebra 2 help please

Answer 1

hmm

Answer 2

Is the middle number 15 or 16?

Answer 3

sorry bout that I did the math wrong because the original equation is 4(x+2)^2-3 and you end up with 4x^2+16+11 when youre done right? and then you have to graph it

Answer 4

I like better 4(x+2)^2-3 than the other one!

Answer 5

it says to graph the equation... idk which one though

Answer 6

It is easier to graph!

Answer 7

It tells me right away that the graph is concave up, and has the vertex at -2,-3.

Answer 8

oh yah it is graphing the function not the standard for of it

Answer 9

sorry bout that haha but I still need help... im terrible with functions

Answer 10

Well, let f(x)=4*(x+2)^2-3
compare with the form f(x)=a(x-h)^2+k
we see that the vertex (h,k) is at (-2,-3).
With me so far?

Answer 11

yah so far... just making sure... the vertex is the middle point of the parabola right? like the point in the middle

Answer 12

Right, through the line of symmetry. It is also the trough in this case.
We also know that the leading coefficient (x^2) has a positive coefficient of 16, so it is concave up.

Answer 13

ok so then what

Answer 14

Now we need the zeroes of the function f(x), and the y-intercept. After that we're done.
Are you able to do the two last steps?

Answer 15

what? is there some way you can show me? im better if I can see it... sorry

Answer 16

well actually... how do we find the zeros of the function and the y int?

Answer 17

@mathmate ?

Answer 18

Well, you would use the quadratic formula to solve for the zeroes.

Answer 19

That is when
f(x)=4*(x+2)^2-3=0
you need to find the values of x when f(x)=0.
The expanded version of the function is
f(x)=4*x^2+16*x+13=0
use the quadratic formula to find the values of x.
a=4
b=16
c=13
The zeroes are not integers.

Answer 20

sorry I was out of the house @mathmate

Answer 21

ok so -16+ or minus the square root of 16^2-4(4)(13) all divided by 2(8)

Answer 22

And the y-intercept?

Answer 23

ok so the end I got -16+ or - the sqrt of 48/ 16

Answer 24

I think it's all divided by 8 instead of 16.

Answer 25

oh yah sorry I multiplied by 2 2 times

Answer 26

which equation do I use to find the y int?

Answer 27

The y intercept is equal to f(0), which means that it is the constant term of the function.

Answer 28

yah I know that but I don't know which equation to use? the f(x)=4(x+2)-3???

Answer 29

After that you're done. I will show you a sketch where to fit things in.
Annotate these points with an x-y pair, such as (0,13).

Answer 30

I don't know what equation to use for the y int... is it the 4x^2 +16x+11 or the 4(x+2)-3

Answer 31

@mathmate if I know which equation to use for the y int then I will be able to do it but I don't know which one to use... I think its the 4x^2+16x+13 so the y int would be 13 right?

Answer 32

@mathmate come on were almost done! :) I wana finish this :)

Answer 33

@Phebe

Answer 34

im here nd where's the question

Answer 35

graph f(x)=4*(x+2)^2-3