.
Do you know your Pythagorean Identities for your trig functions?
Alright, so if you had to solve that for sin^2 theta, what would you get?
http://www.wolframalpha.com/input/?i=%281-cos%5E2%28x%29%29%2F%281-cos%28x%29%29
this might be helpful idk
Give me a minute to check on all my identities so I take you the shortest, most direct way here, ok?
one solution multiply the top and bottom by 1 + cos theta use the identity 1- cos sq theta = sin sq theta divide by sin sq theta 1 + cos theta
Here is my step by step It's long but it makes sense. I go about things the long way usually because I don't skip a step or make an error. The first line would be|dw:1402284395326:dw|because this is one of our double angle identities. The next line would be|dw:1402284498231:dw|because cos(2x) = 2 cos^2x - 1. The next line would be|dw:1402284569233:dw|There I added the 1 and the 1 after I changed the sign inside the parenthesis. Next would be|dw:1402284676200:dw|Now the numerator is the difference of perfect squares that actually factors very nicely!|dw:1402284821928:dw|
Join our real-time social learning platform and learn together with your friends!