Question

8 X 10^(2x-7) = 3
Need help solving the exponential/logarithmic function

Answer 1

divide both sides by 8, then take the base ten log of both sides... what do u get as a result?

Answer 2

\[ 8 \times 10^{2x-7} = 3\\
10^{2x-7}=\frac{3}{8}\\
\log(10^{2x-7})=\frac{3}{8}\\
(2x-7)\log10=\log\left( \frac{3}{8}\right)\\
2x - 7 = \log\left( \frac{3}{8}\right), \text{since }\log10=1\\
2x = \log\left( \frac{3}{8}\right)+7\\
x = \frac{\log\left( \frac{3}{8}\right)+7}{2}\]