the mass spectrum of ethanol consists of lines at m/e = 15,28,31,45 and 46. Write the formula of all the ions responsible for these lines @Abhisar
hope u can help me out
@ParthKohli
@Somy
ah no i don't really know this.. im sorry :(
Since there are only a few fragmentation patters for small molecules, like ethanol, you can play around with the molar masses of the atoms and guess them. It makes it easier if you take inventory 6 H 1 g/mol 2 C 12 g/mol 1 O 16 g/mol Now we just look for combinations that give you those mass-to-charge ratios 15 m/e -> 1 C + 3 H = 12 + 3 = 15 so this is \(CH_3^+\) 28 m/e -> 2 C + 4 H = 24 + 4 = 28 this is \(C_2H_4^+\), it looks like |dw:1402374691304:dw| you might also think that you can have 1 O + 1 C because it also adds up to 28, but that's unlikely because the ion needs to be stable. Try the rest
31 m/e = \[C _{36} H _{5}\] Is it correct @aaronq
\(C_{36}\)? but you only have 2 carbons
can u show how to get the correct answer for m/e 31
\[CH _{2}\] ?
hm lets see if we have 1 O and 1 C, then were at 16+12=28, if we add 3 H's then were at 31.|dw:1402416675830:dw|
remember that were working with the molar masses of the atoms, they must add up to the values given.
ok, how do I add 3H's
each H has a mass of 1, so 28 +3 = 31. When you're learning this you should always be working with pictures to aid you visualize the fragments.
Understood
Thanks @aaronq
No problem, try it again, if you dont get it i'll look at it later. I have to go
|dw:1402417121812:dw| m/e 45
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