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2x^2-8/3x+3/2=2/3 solve equation
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@Arnab09
is it like this? \[2x ^{2}-8/3 x +3/2 = 2/3\]
yes but i figured it out. can you help me with different one then?
ok, post the question
{6x-5y=10 10x-5y=-10
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in this particular case, if you subtract the first equation from the second one, you will be left with 4x=-20, or x=-5 put that value of x in any of those 2 equations and you will get the value of y
what about this one? (4x^2)^3 (-2x^5)(-7x^6) simplify
@Arnab09
you know the rule of indices?
no
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at the first part you are cubing x^2, so it will be x^6, cube -4 as well, it will be -64 x^6
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