Algebra 2 help. Medal!
??
@ganeshie8
heard of `discriminant` before ?
I don't know exactly what it is but I know the formula -b-4ac
\(\large b^2 - 4ac\) is called the discriminant
start by finding the discriminant of first function : \(\large f(x) = x^2+6x-16\)
ok so 6^2-4(1)(-16)
\(\large a = 1\) \(\large b = 6\) \(\large c = -16\) discriminant =\(\large b^2-4ac = ?\)
Yes ! simplify
is it plus or minus 64
its either -28 or 100 but I don't know which one
im pretty sure its 100
6^2-4(1)(-16) 36 + 64 100
You're right !
sweet now how do I figure out if its 2 irrational solutions or 2 rational solutions
and since the dicriminant is a perfect square(100 = 10^2), f(x) must have `Two real rationals solutions`
ohhhhh ok thank you! so what about the second equation
find the discriminant for second equation also
it would be 6^2-4(1)(1) so the next one would be 32
Yes !
but im still confused with the conditions...
and since the dicriminant is > 0, but not a perfect square), g(x) must have `Two real irrational solutions`
ohhhh yes I get it now!!! :) :) :)
Here are the conditions : discriminant > 0, and a perfect square : two different real RATIONAL solutions discriminant > 0, and NOT a perfect square : two different real IRRATIONAL solutions discriminant = 0 : two same real rational solutions discriminant < 0 : two complex solutions
good :)
ok thank you! can you help with a couple more?
I'll try... ask them in a separate post :)
ok hang on
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