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A farmer has 2,000 ft of fencing. He wants to enclose his chickens, pigs and sheep in three separate rectangular sections. What width would maximize the area of the complete rectangular enclosure?
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The case where the rectangle is a square always maximizes the area. If you search under the web for 'given a fixed perimeter, why does a square maximize area?' you'll get several explanations. Look for the explanations that don't use calculus.
but how would I solve it? I tried looking online but I couldn't exactly figure it out
i was trying to find the actual measurements if the length l= width w then area of rectangle lw becomes area = w^2 largest perfect square of 2000 rt of (4 x 5 x 100) = 20rt5
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