I need to find the four arithmetic means between -21 and -36
\(\large\color{darkblue}{ \rm -21,~~\text{_},~~\text{_},~~\text{_},~~\text{_},~~36. }\) \(\large\color{darkblue}{ \rm -21+5d=-36. }\) \(\large\color{darkblue}{ \rm 5d=-15. }\) \(\large\color{darkblue}{ \rm d=-3. }\) \(\large\color{darkblue}{ \rm 21,\color{red} { ~-24,~-27,~-30,~-33,} ~-36 }\)
:O THANKYOUU! pleaseee help me with another onee!!
I need to find the four arithmetic means between 100 and 135
can you try it based on the previous problem ?
100+5d=135?
100, ` ___ ` ` ___ ` ` ___ ` ` ___ ` 135 yes... !
Find the d
(d is the difference btw the terms )
`100+5d=135 ` 1) subtract 100 from both sides 2) divide both sides by 5
5d=35?
yes and divide both sides by 5 ?
d = ?
d=7?
So can you fill in the blanks ? 100, `___` `___` `___` ___` 135
107,114,121,128?
Yeeeah !!
THANKYOUUUU so muchh!
So when you have N arithmetic means between A and B you say A+Nd=C and solve for d, knowing the number of means N and knowing the number A and B makes sense ?
it does thankyou soo much! would you help me with one more? please:)?
Sure :)
What is the 20th term of the following arithmetic sequence? 1/2, 1, 3/2, 2
1 - 1/2 = ? (this would be the difference - what you add to each term, to obtain the next term. ) (for the beginning )
So ` d = ½ `
ok :)?
now use the formula, \(\large\color{darkblue}{ \rm a_1+d(n-1)=a_n }\) In your case, \(\large\color{darkblue}{ \rm \frac{1}{2}+ \frac{1}{2}(20-1)=a_{20} }\) Makes sense ?
yes totally! so..
Can you find the \(\large\color{black}{ \rm a_{20} }\) ?
½ + ½(20-1) = A 20 ½ + ½(19) = A 20 ½(1) + ½(19) = A 20 ½(20) = A 20 10=A 20
1(19)=a20?
See how I am getting A20 ?
I see now, ok I think I got it!
THANKYOUUUU!!!! :)
Anytime :)
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