Mathematics
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OpenStudy (anonymous):
Find the sum of the infinite geometric series 8+4+2+1...
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hartnn (hartnn):
could you find the common ratio 'r' ?
OpenStudy (anonymous):
-2?
hartnn (hartnn):
the sum for infinite geometric series is
\(\Large S_n = \dfrac{a_1}{1-r} \)
hartnn (hartnn):
how ?? you know what common ratio is, right ?
OpenStudy (anonymous):
the difference between the values?
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hartnn (hartnn):
nopes,
common ratio is the ratio between consecutive terms
r = 2nd term/ 1st term = 3rd term / 2nd term = .... and so on
hartnn (hartnn):
like if i had 27,9,3,1,....
then r = 9/27 = 3/9 = 1/3
OpenStudy (anonymous):
so 0.33?
hartnn (hartnn):
that was just an example :P
your sequence is
8+4+2+1...
r = ... ?
hartnn (hartnn):
r = 4/8 = 2/4 = .... ?
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OpenStudy (anonymous):
0.5? or 2?
hartnn (hartnn):
its r = 1/2 (which also = 0.5)
now plug in values in the formula
hartnn (hartnn):
\(a_1\) = 1s term = 8 here
OpenStudy (anonymous):
what is a1?
OpenStudy (anonymous):
first term is also 8
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hartnn (hartnn):
a1 is the notation for 1st term
and in this sequence it = 8
hartnn (hartnn):
\(\Large S_n = \dfrac{a_1}{1-r} = \dfrac{8}{1-1/2} = ... ?\)
OpenStudy (anonymous):
=4?
hartnn (hartnn):
sure ?
hartnn (hartnn):
\(\dfrac{8}{1/2} = 8\times 2\)
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OpenStudy (anonymous):
16!!! Sorry you are totally right!
THANKYOUUU!!
hartnn (hartnn):
\(\huge \color{red}{16 ~~\checkmark \quad \ddot \smile}\)