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Mathematics 15 Online
OpenStudy (anonymous):

How to graph x+4y<8 and -x+2y>2 ?

OpenStudy (baseballer2014):

you first have to solve for y in each of the equations do you know how to do that?

OpenStudy (baseballer2014):

y=mx+b is the form in which you can graph an equation

OpenStudy (anonymous):

I assumed I needed to divide on both sides so the form will come out as x< ? . I know how to graph it once it is in the correct form, but I am confused on how to get there.

OpenStudy (baseballer2014):

\[x+4y<8\] \[4y<-x+8\] \[y<-x/4 +2\] that is the first equation

OpenStudy (pinksapphire):

x+4y<8 -x -x 4y<8-x 4y/4<8-x/4 y<2-1/4x For the other inequality... -x+2y>2 +x +x 2y>2+x 2y/2>2+x/2 y>1+1/2x

OpenStudy (baseballer2014):

\[-x+2y>2\]\[2y>x+2\]\[y>x/2+1\] that is the second equation

OpenStudy (pinksapphire):

It's not an equation...

OpenStudy (pinksapphire):

Or is it?

OpenStudy (baseballer2014):

inequality* you should have put it into y=mx+b form its easier to graph

OpenStudy (baseballer2014):

now when graphing it look at the slope which is the mx part and that is rise over run so for the first inequality go up 2 units from 0,0 and then from that point (2,0) down 1 over 4 and draw a line. For the second equation u will go up 1 from 0,0 and then from that point (1,0) up 1 over 2. so do that and tell me when you are done

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