How to graph x+4y<8 and -x+2y>2 ?
you first have to solve for y in each of the equations do you know how to do that?
y=mx+b is the form in which you can graph an equation
I assumed I needed to divide on both sides so the form will come out as x< ? . I know how to graph it once it is in the correct form, but I am confused on how to get there.
\[x+4y<8\] \[4y<-x+8\] \[y<-x/4 +2\] that is the first equation
x+4y<8 -x -x 4y<8-x 4y/4<8-x/4 y<2-1/4x For the other inequality... -x+2y>2 +x +x 2y>2+x 2y/2>2+x/2 y>1+1/2x
\[-x+2y>2\]\[2y>x+2\]\[y>x/2+1\] that is the second equation
It's not an equation...
Or is it?
inequality* you should have put it into y=mx+b form its easier to graph
now when graphing it look at the slope which is the mx part and that is rise over run so for the first inequality go up 2 units from 0,0 and then from that point (2,0) down 1 over 4 and draw a line. For the second equation u will go up 1 from 0,0 and then from that point (1,0) up 1 over 2. so do that and tell me when you are done
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