Will FAN and MEDAL A plane is located at C on the diagram. There are two towers located at A and B. The distance between the towers is 7,600 feet, and the angles of elevation are given. a. Find BC, the distance from Tower 2 to the plane, to the nearest foot. b. Find CD, the height of the plane from the ground, to the nearest foot.
@jim_thompson5910 @Hero @satellite73 @ganeshie8
@mathstudent55
its easy .. u just need to revise the basic sine and cosine functions
because u dnt knw the full lenght of base .. u will be two equations in 1 variable .. so at the end u will solve them and give the results ..
hmm, alright
?
Oops I forgot what we were solving for! Anyways... first we take the sine of the two angles we are given... so sin 16 = CD/AD and sin24=CD/BD
And we can also relate AD and BD because AD-BD=7600ft (check graph to see how this makes sense)
Now... if we can find BD (which you can by using the equations I posted) we will be able to solve for BC
So do you have any ideas how to solve for BD?
\[\frac{ BC }{\sin16 } =\frac{ 7,600 }{ \sin8 }\]
maybe?
hmm let me just check what you did there
yes you are correct! And that way is much faster than what I was doing. Now that you have BC, you will probably notice that you can use sin24 to find the CD
Im not so sure, the equation is as far as I got
Do you know how to solve for BC?
yes, I got 122.7 ft
well at least thats what i got
@timely
Sorry! I had a problem with my internet connection. 122.7 feet seems very very low for length BC
\[\frac{ BC }{ \sin16 }=\frac{ 7600 }{ \sin8 }\] isolate BC by multiplying both sides by sin16 \[(\sin16)\frac{ BC }{ \sin16 }=\frac{ 7600 }{ \sin8 }(\sin16)\] as you can see... sin16 cancels out on left side \[BC =\frac{ 7600 }{ \sin8 }(\sin16) \approx 15052.07464\]
so just round BC to the nearest foot for that answer... and now that you have BC, you can solve for CD with sin24=CD/BC
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