ok i need someone to help me. I have the answer but dont know how to make the square root nto a decimal. I will try and draw it

Question

anonymous · Answer

a 24ft ladder is placed against a verticle wall. with the bottom of the ladder standing level 2ft fro the base of the building. how high up does the ladder reach.
I got $$\sqrt{1}$$ bt it has to b a decimal.how do I do that?

vishweshshrimali5 · Answer

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vishweshshrimali5 · Answer

@tena32 I think your answer is wrong. I suggest you to give it another try.

vishweshshrimali5 · Answer

Try to use pythogoras theorem,

and if you did the same earlier then please check your calculations again.

anonymous · Answer

this site was running funny and it didn't type my other number in. it was supposed to be 23 not 2

vishweshshrimali5 · Answer

Even then you have done some mistake.

Let the required height be h. Then according to the figure (that I drew), since, the triangle is a right angled triangle, I have,

By pythogoras theorem,

(height)^2 + (base)^2 = (hypotenuse)^2
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vishweshshrimali5 · Answer

@tena32, did you get it correct now ?

usman1995 · Answer

u need to apply Pythagoras theorem...... uderoot(2^2+24^2) solve it u get 24.08 ft

usman1995 · Answer

oh if it was supposed to be 23 instead of two just put 23 in Pythagoras theorem where i've put 2 and u'll get the right answer

usman1995 · Answer

$$\sqrt{23^{2}+24^{2}}$$

usman1995 · Answer

anwser is 33.24ft