Using synthetic division how do i find the quotient and remainder (12x^4+5x^3+3x^2-5)/(x+1)
start by setting up the coefficients for synthetic division process
-1 | 12 5 3 0 -5 | ------------------------------------
seen this before ?
yeah looks familiar now
good :) step 1 : drop the 12 down to the last row : -1 | 12 5 3 0 -5 | ------------------------------------ 12
then don't you bring 12 up to the next?
step2 : multuply -1*12 and put the result in the next column : -1 | 12 5 3 0 -5 | -12 ------------------------------------ 12
step3 : add "5, -12" and put the result down in the last row : -1 | 12 5 3 0 -5 | -12 ------------------------------------ 12 -7
just repeat step2 and step3 till the end..
I got -1| | 12 -7 10 10 -15?
Very good try ! but looks like there is a mistake, let me show u the work
remainder is 5
-1 | 12 5 3 0 -5 | -12 7 -10 10 ------------------------------------ 12 -7 10 -10 5
oooooh okay
would the remainder be -1 ?
remainder = last number in the last row
oooooh haha yikes thanks
-1 | 12 5 3 0 -5 | -12 7 -10 10 ------------------------------------ 12 -7 10 -10 | 5
and the quotient ?
remainder = 5
quotient is formed by the coefficients in the last row : 12x^3 - 7x^2 + 10x - 10
|dw:1402383912935:dw|
Join our real-time social learning platform and learn together with your friends!