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Mathematics 16 Online
OpenStudy (anonymous):

Using synthetic division how do i find the quotient and remainder (12x^4+5x^3+3x^2-5)/(x+1)

ganeshie8 (ganeshie8):

start by setting up the coefficients for synthetic division process

ganeshie8 (ganeshie8):

-1 | 12 5 3 0 -5 | ------------------------------------

ganeshie8 (ganeshie8):

seen this before ?

OpenStudy (anonymous):

yeah looks familiar now

ganeshie8 (ganeshie8):

good :) step 1 : drop the 12 down to the last row : -1 | 12 5 3 0 -5 | ------------------------------------ 12

OpenStudy (anonymous):

then don't you bring 12 up to the next?

ganeshie8 (ganeshie8):

step2 : multuply -1*12 and put the result in the next column : -1 | 12 5 3 0 -5 | -12 ------------------------------------ 12

ganeshie8 (ganeshie8):

step3 : add "5, -12" and put the result down in the last row : -1 | 12 5 3 0 -5 | -12 ------------------------------------ 12 -7

ganeshie8 (ganeshie8):

just repeat step2 and step3 till the end..

OpenStudy (anonymous):

I got -1| | 12 -7 10 10 -15?

ganeshie8 (ganeshie8):

Very good try ! but looks like there is a mistake, let me show u the work

OpenStudy (usman1995):

remainder is 5

ganeshie8 (ganeshie8):

-1 | 12 5 3 0 -5 | -12 7 -10 10 ------------------------------------ 12 -7 10 -10 5

OpenStudy (anonymous):

oooooh okay

OpenStudy (anonymous):

would the remainder be -1 ?

ganeshie8 (ganeshie8):

remainder = last number in the last row

OpenStudy (anonymous):

oooooh haha yikes thanks

ganeshie8 (ganeshie8):

-1 | 12 5 3 0 -5 | -12 7 -10 10 ------------------------------------ 12 -7 10 -10 | 5

OpenStudy (anonymous):

and the quotient ?

ganeshie8 (ganeshie8):

remainder = 5

ganeshie8 (ganeshie8):

quotient is formed by the coefficients in the last row : 12x^3 - 7x^2 + 10x - 10

OpenStudy (usman1995):

|dw:1402383912935:dw|

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