convert to a fraction 0,081081081
\[\frac{ repeating digits }{ 10^{number of repeating digits} }\]
then simplify your fraction..
do it @jesi1201
sorry, i forgot that its a repeating decimal... i first thought of a terminating decimal.. my bad..
can u do it .. if so then plz do it ..
is the given 0.081081081... right? with 081 repeating?
ok then
081 block is repeating after decimal point .. how to solve
if it's a repeating decimal, let n=0.081081... (eq. 1) multiply both sides by 10^3, since there are 3 repeating digits... we have, 1000n = 081.081081... (eq. 2) subtract eq 1 from eq 2, that is 1000n = 081.081081... - n = 0.081081... ___________________________________ 999n = 81 \[n = \frac{ 81 }{ 999}\] simplify...
well i have another idea .. to multiply it by 1000 and subtracting the same number from result will make it definite number i think wat do u say @jesi1201
oh ya u did the same
ya its done thank u @jesi1201 u made some thing fresh to me that i learned 8 years ago :P
thanks, sorry again for my mistake earlier...
no its ok . actuallly i did nt get that mistake so i asked u
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