Question

If you're good at Algebra 2 please help (Medal)

Answer 1

@ganeshie8 @SolomonZelman

Answer 2

@mathslover

Answer 3

vertex form :
f(x) = a(x-h)^2 + k

Answer 4

when is your birth day ?

Answer 5

2-3

Answer 6

month = 2
day = 3

?

Answer 7

yessir

Answer 8

h = month = 2
k = day = 3

lets say a = 1

Answer 9

plug them in the vertex form :
f(x) = 1(x-2)^2 + 3

Answer 10

thats part 1^

Answer 11

ok

Answer 12

part one meaning number 1?

Answer 13

yes

Answer 14

ok haha just making sure

Answer 15

for part 2 :

Expanding the function using the identity (a-b)^2 = a^2 – 2ab + b^2 gives :
f(x) = 1(x^2 – 4x + 4) + 3

combining the like terms :
f(x) = x^2 – 4x + 7

Answer 16

wow that was really easy haha ok now the graphing part is hard for me

Answer 17

you dont need to graph it manually, just graph it in geogebra and attach the snap

Answer 18

do u have geogebra ?

Answer 19

how do I do that? I need to attach it to the assignment thing in flvs

Answer 20

graph it here
https://www.desmos.com/calculator

Answer 21

do I have to download it?

Answer 22

no, you can graph it online

Answer 23

ok

Answer 24

here is the graph :
http://prntscr.com/3rgy6p

Answer 25

oh ok thank you so much now how do I save that so I can attach it?

Answer 26

click the link : https://www.desmos.com/calculator

just enter below function in the input bar :
f(x) = x^2 – 4x + 7

Answer 27

oh ok I got it now the last one :)

Answer 28

And thank you so much man

Answer 29

and here is what she wrote the last time I did this alone ignore the partner one bc she messed up

Answer 30

so im confused bc shes saying different questions like what happens when a is changed and If you know the x values of the points, what else do you need to find before you can plug it in to find the rate of change and So how does changing the months or h change the graph? If it was 2 months earlier how would it move specifically?
How would changing the day or k affect the graph? If it was 5 days later how specificially would it move the graph? its just weird because there are only those 4 questions and she added more

Answer 31

@ganeshie8 can you help me with the last part

Answer 32

Sorry was afk.. here is the last part :
f(x) = x^2 - 4x + 7

To get the average rate of change for f(x) from x = 4 to x = 7, f(4) and f(7) need to be evaluated first and then they need to be plugged intot he average rate of change formula :

Average rate of change = \(\large \dfrac{f(7) - f(4)}{7-4}\)

f(7) = 7^2 - 4(7) + 7 = 49 - 28 + 7 = 49 - 21 = 28
f(4) = 4^2 - 4(4) + 7 = 16 - 16 + 7 = 0 + 7 = 7

Average rate of change = \(\large \dfrac{28-7}{7-4} = \dfrac{21}{3} = 7\)

Answer 33

so its 7?

Answer 34

and what should I do about what my teacher said?

Answer 35

hi

Answer 36

not sure

Answer 37

what would you do?

Answer 38

ugh I emailed my teacher and she said she wants me to let her know what would happen in those instances @ganeshie8 so could you help me please