geometry help
You need to solve 4 and 5?
I can help you with these two now. Then I have to go.
Let's do 5 first. The geometric mean, x, of numbers a and b is: \(\dfrac{a}{x} = \dfrac{x}{b}\) Cross multiplying, you get: \(x^2 = ab\) \(x = \sqrt{ab} \) What this shows you is that to find the geometric mean of two numbers, all you need to do is multiply the numbers together and take the square root.
What do you get for 5?
12
Have you tried problem 5 yet? I have to go very soon, and I'd like to get to 4 also.
No. How did you get 12? Show me the steps. The first step is multiplying 32 and 8 together. What do you get?
ok whats the next step
256
I wrote this above: "What this shows you is that to find the geometric mean of two numbers, all you need to do is multiply the numbers together and take the square root."
Good. 256 is correct. Now you need to take the square root of 256.
is it 20
i dont nohow to get the square root
No. 20 * 20 = 400 You need a number that when multiplied by itself gives you 256. That's what square root means. Do you have a calculator?
ok it 16
You asked 12 before. 12 * 12 = 144 Then you asked about 20. 20 * 20 = 400 Since you need the square root of 256, the answer is between 12 and 20.
Great. Now you got it. That is the correct answer for 5.
Now let's do problem 4.
ok number 4
To prove two triangles similar, you need one of the 4 reasons that are given as choices. Let's look at the choices, and see which one we can use.
First, I have a question for you. Look at these two lines, and angles 1 and 2. What are angles 1 and 2 called and what do you know about their measures. |dw:1402426743073:dw|
I have to go. Answer quickly, or I'll just sign off.
i dont no
right triangles
They are vertical angles and their measures are the same.
90 degree
ohh AA
postulate
so sss
From the vertical angles, you get one pair of congruent angles. You are given one pair of congruent angles. That means you have two pairs of congruent angles. Answer is AA~ Postulate.
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