Question

Factor completely: x^2 − 3x + 5

Answer 1

@iambatman

Answer 2

I think this is unfactorable?

Answer 3

which is prime?

Answer 4

\[x^2-3x+5 = 0 \]

Complete the square

\[x^2-3x = -5\]

\[x^2-3x+\frac{ 9 }{ 4 }=-\frac{ 11 }{ 4 }\]

\[(x-\frac{ 3 }{ 2 })^2=-\frac{ 11 }{ 4 }\]

Eliminate the exponents now, and you'll get complex answers.

Answer 5

cuz i was thinking it was prime idk

Answer 6

is that considered prime or?

Answer 7

... u wont be able to factorise tht

Answer 8

Like I said you'll get complex roots.

Answer 9

\[x = (3\pm \sqrt{11}i)/2\]