Mathematics
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OpenStudy (anonymous):
Somebody help! Will FAN and MEDAL
Simplify the trig expression
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OpenStudy (anonymous):
OpenStudy (anonymous):
@jim_thompson5910
OpenStudy (anonymous):
@satellite73
jimthompson5910 (jim_thompson5910):
Start off with the idea that
cos^2 + sin^2 = 1
jimthompson5910 (jim_thompson5910):
what is cos^2 in terms of sin?
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OpenStudy (anonymous):
Hmm, like the reciprocal identity?
jimthompson5910 (jim_thompson5910):
how would you isolate cos^2
jimthompson5910 (jim_thompson5910):
in the equation cos^2 + sin^2 = 1
OpenStudy (anonymous):
cos^2= sin^2 + 1 ?
jimthompson5910 (jim_thompson5910):
close but no
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OpenStudy (anonymous):
is it minus one?
jimthompson5910 (jim_thompson5910):
cos^2 = 1 - sin^2
OpenStudy (anonymous):
Ohh
OpenStudy (anonymous):
Thats one of the indentities
jimthompson5910 (jim_thompson5910):
yes, the pythagorean identity
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OpenStudy (anonymous):
so that would mean cos^2 is equal to 1
jimthompson5910 (jim_thompson5910):
no
OpenStudy (anonymous):
Oh okay, I'm lost again then
jimthompson5910 (jim_thompson5910):
do you see how cos^2 + sin^2 = 1
OpenStudy (anonymous):
yes
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jimthompson5910 (jim_thompson5910):
do you see how I'm getting cos^2 = 1 - sin^2
OpenStudy (anonymous):
yes
jimthompson5910 (jim_thompson5910):
So...
\[\Large \frac{\cos^2(\theta)}{1 - \sin(\theta)}\]
\[\Large \frac{1-\sin^2(\theta)}{1 - \sin(\theta)}\]
what's next?
OpenStudy (anonymous):
Simplify by canceling out?
jimthompson5910 (jim_thompson5910):
that comes later
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OpenStudy (anonymous):
I'm not sure then
jimthompson5910 (jim_thompson5910):
factor the numerator
OpenStudy (anonymous):
Like (sin) (sin)?
jimthompson5910 (jim_thompson5910):
kinda
jimthompson5910 (jim_thompson5910):
you'd use the difference of squares rule
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OpenStudy (anonymous):
Okay I factored it, well I tried anyway.. is it 1-sin?
OpenStudy (anonymous):
(1-csc)(1+csc) ?
jimthompson5910 (jim_thompson5910):
closer but no
OpenStudy (anonymous):
Or am I just not getting this at all?
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OpenStudy (anonymous):
Aw poop, okay hold on
OpenStudy (anonymous):
Actually, never mind, I don't think I am getting it
jimthompson5910 (jim_thompson5910):
use
a^2 - b^2 = (a-b)(a+b)
jimthompson5910 (jim_thompson5910):
a = 1
b = sin(theta)
OpenStudy (anonymous):
(1-sin)(1+sin) ?
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jimthompson5910 (jim_thompson5910):
yep
OpenStudy (anonymous):
YES
jimthompson5910 (jim_thompson5910):
you'll notice something cancelling
OpenStudy (anonymous):
Okay, I should get 1+sin
jimthompson5910 (jim_thompson5910):
yep
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OpenStudy (anonymous):
Thank you so much! (: