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OpenStudy (anonymous):
how to find the lateral side surface of the area of a cone... segment y=1/4x from x=0 to x=9 about the x-axis.
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OpenStudy (anonymous):
liket his ?
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OpenStudy (anonymous):
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OpenStudy (anonymous):
Yes!
OpenStudy (anonymous):
wanna use geometry or calcules ?
OpenStudy (anonymous):
Calc
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OpenStudy (anonymous):
use the formula for the area of a surface of revolution obtained by rotating the graph curve about the x-axis ,, do u have it ?
OpenStudy (anonymous):
in ur tt book ?
OpenStudy (anonymous):
i guess around y its
\(\large 2\pi \int_a^b x.\sqrt {1+f'(x)^2 } dx \)
we should make it around y T_T
OpenStudy (anonymous):
wait i ment we need it around x..
OpenStudy (anonymous):
Mhmm!
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OpenStudy (anonymous):
So far I have most of it filled in, I'm just missing the dy/dx
OpenStudy (anonymous):
The y=1/4x ?
OpenStudy (anonymous):
And, the dy/dx = 1/2rootx ?
ganeshie8 (ganeshie8):
\[\large SA = \int \limits_0^9 2\pi y ~ ds = \int \limits_0^9 2\pi \left(\frac{1}{4}x\right) \sqrt{1 + \left(\dfrac{dy}{dx}\right)^2} ~dx\]
ganeshie8 (ganeshie8):
\(\large y = \dfrac{1}{4}x \implies \dfrac{dy}{dx} = ?\)
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