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OpenStudy (anonymous):

How many moles of potassium hydroxide are necessary to form 0.636 moles of potassium sulfate?

OpenStudy (abmon98):

KOH has a Mr of 56grams K2SO4 has a Mr of 174grams so x moles gives 56 grams 0.636-->110 grams of potassium sulphate X=56*0.636/110=0.32moles

OpenStudy (jfraser):

you need a balanced reaction to do this properly

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