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3y-2x+z-2x+3(x+y) A. -x+4y+z B. -x+6y+z C. x+4y+z D. 3x+4+z
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Answer is B
3y - 2x + z - 2x + 3(x + y) --- distribute through the parenthesis 3y - 2x + z - 2x + 3x + 3y -- now combine like terms -2x - 2x + 3x = -4x + 3x = -x 3y + 3y = 6y and then there is the z put it all together and you get : -x + 6y + z Just thought you might want to see how the answer was found :)
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