Hello! I need someone to explain to me how to do this. Thanks!!!
Let the fourth vertex be (x, y). Diagonals AC and BD bisect each other => their mid-points are the same Start this way
I HAVE NO CLUE WHAT YOU JUST SAID @.@
|dw:1402537206318:dw| So now we must figure out that point correct? Look at the difference from each x point around the square and each y point around the square
since our missing point is on the bottom left side, the x coordinate for the bottom left is -4 because that is what the top right x coordinate is and they have the same x just like the two corners on the right have the same x and it goes the same for y, the bottom right point has a y value of -4 so that means the missing point has a y value of -4
I don't get it
Or you didn't read it ??
look at the left side of the square! it is -4 units away from the (0,0) so now that means both corners are -4 units away from 0,0 because they connect straight down. Correct?
@jigglypuff314 if she cannot understand my logical reasoning that is simple to find the answer, she is deffinetly not going to understand the mathematical procedure required to find the answer
(-4,-4) is the answer. In a square all the sides are equal. So find the distance between the sides using the formula \[\sqrt{(y2-y1)^2+(x2-x1)^2}\]
look at the picture baseballer drew for you, see that each point is two units away from each other. from (-4, -2) go down two units, that will give you the point you are looking for
@Harsha19111999 , that was just what she was looking for BUT Please try to avoid giving such direct answers, it is against OpenStudy's code of conduct http://openstudy.com/code-of-conduct This site has a policy for "Give Help, Not Answers" violations of such policies could potentially result in an account suspension or ban.
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