you have 755.0 ml of a 0.870 M solution of Pb(NO3)2.
how many moles of lead (II)nitrate are present?
how many nitrogen atoms are present?

Question

you have 755.0 ml of a 0.870 M solution of Pb(NO3)2.
how many moles of lead (II)nitrate are present? 
how many nitrogen atoms are present?

koikkara · Answer

Welcome to Open Study !!  @ab95

anonymous · Answer

@Koikkara thanks

koikkara · Answer

@Vincent-Lyon.Fr Hope you might be able to help Him/Her !

vincent-lyon.fr · Answer

Tip: use the formula that links amount of matter, volume, and concentration.

anonymous · Answer

Pb(NO)3 = 331.22 mol. 
im not sure what formula to use

anonymous · Answer

$\large\color{blue}{Welcome~ to~open ~ study ~ab95!}$
To figure out this question, you must understand the relationship between moles, volume and concentration. And it is governed by the formula,
$n= C.V$
Where $n$ is the number of moles of the particular compound/element, $C$ is concentration of the same compound/element in $\dfrac{mol}{L}$ ,and $V$
 is volume of that compound/element in $L$.

sweetburger · Answer

dont you mean grams ab95

anonymous · Answer

@AnImEfReaK thanks

anonymous · Answer

To find the number of nitrogen atoms inacompound,find the moles of nitrogen using mole ratio. How many nitrogen atoms are in that element?
So you would multiply the moles of the compound by the number of nitrogens.
Then to find number of atoms use this formula,
$N=Avogadro's~number.n$
$   =6.0222 .10^23 . n$
N will be the number of moles of nitrogen.