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use the trigonometric ratios for a right triangle to derive a cofunction identity for tan(90degrees-A)
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so do you know SOH CAH TOA? in this case TOA ==> Tan (theta) = Opposite/ Adjacent so theta = 90 - A which means its a right angle triangle with 90 degrees for one angle, A degrees for the other angle, and (90-A) degrees for the 3rd angle
|dw:1402560974743:dw| does this make sense???
that makes sense but how do I derive the cofunction identity using the trig ration\[tantheta=1/\cot\]
Another hint: \[tan \theta=opp/adj\] \[cot \theta=adj/opp\] and study Jack's diagram again.
I'm just having trouble applying this, how can I figure any side out from just one angle?
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